Trigonometric Substitutions
Evaluate the following integrals using trigonometric substitution:
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\( \displaystyle{\int \frac{x}{\sqrt{4-x^2}} \ dx} \) Solution ↗
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\( \displaystyle{\int \frac{x^2}{\sqrt{9-x^2}} \ dx} \) Solution ↗
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\( \displaystyle{\int \frac{\sqrt{x^2-4}}{x} \ dx} \) Solution ↗
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\(\displaystyle{ \int_0^1 x^3 \sqrt{1-x^2} \ dx}\) Solution ↗
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\( \displaystyle{\int \frac{1}{\sqrt{4+x^2}} \ dx }\) Solution ↗
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\( \displaystyle{\int \frac{\sqrt{x^2+ 1}}{x} \ dx}\) Solution ↗
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\( \displaystyle{\int \frac{x^3}{\sqrt{x^2+25}} \ dx}\) Solution ↗
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\(\displaystyle{\int \frac{x}{\sqrt{x^2-9}} \ dx }\) Solution ↗
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\(\displaystyle{\int \frac{x}{\sqrt{x^2-25}} \ dx }\) Solution ↗
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\( \displaystyle{\int \frac{\sqrt{x^2-25}}{x^3} \ dx}\) Solution ↗
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\( \displaystyle{\int_0^5 \frac{dt}{\sqrt{25+t^2}}}\) Solution ↗