- Find \(f'(x)\) of each of the following functions. solution
(a) \( f(x)=x^2 \) (b) \(
f(x)=x^5 \) (c) \( f(x)=x^{1.8} \)
(d) \( f(x)=x^{\pi} \)
- Find \(f'(x)\) of each of the following functions. solution
(a) \( f(x)= \sqrt{x} \) (b) \( f(x)=\sqrt[5]x\) (c) \( f(x)=x^{3/4}\)
- Find \(f'(x)\) of each of the following functions. solution
(a) \( f(x) = \dfrac{1}{x} \) (b) \( f(x) = \dfrac{1}{x^5} \) (c) \( f(x) =
\dfrac{5}{x^{1/3}}\)
- Find \(f'(x)\) of each of the following functions. solution
(a) \( f(x)=5x^2+\dfrac{3}{x^2}\) (b) \( f(x)=4\sqrt{x}-10x+7 \) (c) \( f(x)=\dfrac{1}{x^{4/3}}-\dfrac{x^3}{5}+7\pi \)
- Find the derivative of the following functions. soluion
(a) \( f(r)=e^r+r^e \) (b) \( f(x)=x(x^2-5)+e^5 \)
- Find the derivative of the following functions. solution
(a) \( f(s) = \sqrt{s} (s-1) \), (b) \(f(x)=\dfrac{\sqrt{x}+x}{x^2} \)
- If \(\displaystyle{ f(t) = \frac{t^2-3t+1}{\sqrt{t}}} \), find \( f'(t) \). solution
- (a) If \( f(x)= x^3-4x^2+5\pi \), find \( f'(-2) \), and (b) If \( f(x)= x^4 + 2 e^x \), find \( f'(0) \). solution
- (a) If \( f(x)= \sqrt{x} \), find \( f'(4) \), and (b) if \( g(x)= \frac{1}{\sqrt[3]{x}} \), find \( g'(1) \). solution
- Find an equation of the tangent line to the curve \(y= x^4-3x^2+5 \) at \( x=1\). solution
- Find an equation of the tangent line to the curve \(y= \sqrt[4]{x}-x \) at the point \((1,0)\). solution
- The equation of motion of a particle is \( s=t^4-2t^3+t^2-t \). (a) Find the velocity after 1 second.
(b) Find the accelaration after 1 second. solution
- Find the points on the curve \(y=2x^3+3x^2-12x+1\) where the tangent is horizontal. solution
- For what value of \(x\) does the graph of \(f(x)=e^x-2x\) have a horizontal tangent line? solution
- Find the first and second derivatives of the function. solution
(a) \(\displaystyle{f(x)= x^4-3x^3+7x} \)
(b) \(\displaystyle{f(x)= \frac{1}{x^5}} \) (c) \(\displaystyle{f(x)=
\sqrt[5]x}\)
- Find the third derivative of the given function. solution
(a) \(\displaystyle{f(x)= 2x^5+ 8x^2-3x+5}\) (b) \(\displaystyle{f(x)= \frac{1}{x}}\)